Find the energy released in the fission reaction
Answer in units of MeV.
(Info in pic)
- NCSLv 75 years agoFavorite Answer
LHS mass = 1.00867u + 235.044u = 236.05267u
RHS mass = 87.908u + 135.907u + 12*1.00867u = 235.91904u
mass defect = m = 0.13363u * 1.66e-27kg/u = 2.218258e-28 kg
E = mc² = 2.218258e-28kg * (2.998e8 m/s)² * 1MeV / 1.602e-13J
E = 124 MeV ← see edit
EDIT: I copied the mass of Sr incorrectly. Making that correction leads to E = 126 MeV.Source(s): http://en.wikipedia.org/wiki/Atomic_mass_unit http://en.wikipedia.org/wiki/Speed_of_light http://en.wikipedia.org/wiki/Electronvolt
- 5 years ago
.... That's making me feel dumb.