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# How far would a spring, with a spring constant of 350 N/m, have to be stretched beyond equilibrium to produce a velocity of 15 m/s when...?

How far would a spring, with a spring constant of 350 N/m, have to be stretched beyond equilibrium to produce a velocity of 15 m/s when an 800 g mass is attached and released and is allowed to move to the equilibrium position?

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- civil_av8rLv 75 years agoFavorite Answer
KE = SPE

1/2*m*v_max^2 = 1/2*k*x^2

x = v*sqrt(m/k)

x = 15 m/s * sqrt(0.800 kg / 350 N/m) = 0.72 m

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