Calculate the wavelengths of the Kα and Kβ x rays of tungsten? Please help!!!?
The energies for an electron in the K, L, and M shells of the tungsten atom are −69,500 eV, −12,000 eV, and −2200 eV, respectively.
Calculate the wavelengths of the Kα and Kβ x rays of tungsten.
Kα: λ = _____ nm
Kβ: λ = _____ nm
- Steve4PhysicsLv 75 years agoFavorite Answer
The Kα photons are produced by the transition from the L shell to the K shell (see link).
So the photon energy = EL - EK = (−12,000) - (-69,500) = 57,500eV
57,500eV = 57,500 x 1.6x10⁻¹⁹ J = 9.2x10⁻¹⁵ J
λ = hc/E
. .= 6.63x10⁻³⁴ x 3x10⁸/(9.2x10⁻¹⁵)
. .= 2.16x10⁻¹¹ m
. .= 2.16x10⁻¹¹ x 10⁹ nm
. .= 0.0216nm
The Kβ photons are produced by the transition from the M shell to the K shell. Just follow the same procedure as above.