# Calculate the wavelengths of the Kα and Kβ x rays of tungsten? Please help!!!?

The energies for an electron in the K, L, and M shells of the tungsten atom are −69,500 eV, −12,000 eV, and −2200 eV, respectively.

Calculate the wavelengths of the Kα and Kβ x rays of tungsten.

Kα: λ = _____ nm

Kβ: λ = _____ nm

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- Steve4PhysicsLv 75 years agoFavorite Answer
The Kα photons are produced by the transition from the L shell to the K shell (see link).

So the photon energy = EL - EK = (−12,000) - (-69,500) = 57,500eV

57,500eV = 57,500 x 1.6x10⁻¹⁹ J = 9.2x10⁻¹⁵ J

E =hc/λ

λ = hc/E

. .= 6.63x10⁻³⁴ x 3x10⁸/(9.2x10⁻¹⁵)

. .= 2.16x10⁻¹¹ m

. .= 2.16x10⁻¹¹ x 10⁹ nm

. .= 0.0216nm

(check arithmetic)

The Kβ photons are produced by the transition from the M shell to the K shell. Just follow the same procedure as above.

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