Archimedes’ Principle

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Can you solve it, thank you.

1 Answer

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  • 天同
    Lv 7
    6 years ago
    Favorite Answer

    (b) Upthrust on box = 450 kN

    Hence, weight of water displaced = 450 kN

    Mass of water dispalced = 450000/g kg = 4.587 x 10^4 kg

    Volume of water dispalced = 4.587 x 10^4/1025 m^3 = 44.75 m^3

    Thus, h = 44.75/(pi x 2.5^2) m = 2.279 m

    (c) Pressure at half depth = 2 x 800g N/m^2 = 15696 N/m^2

    Total thrust at bottom = 4 x 800g x (pi x 2.5^2) N = 6.16 x 10^5 N

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