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Anonymous asked in Science & MathematicsPhysics · 6 years ago

Please solution... ?

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  • Whome
    Lv 7
    6 years ago
    Favorite Answer

    Length of AD

    Lad = √(0.6² + 0.6² + (2.4 - 0.9)²)

    Lad = 1.723 m

    Length of BD

    Lbd = √(0.6² + 0.6² + 0.9²)

    Lbd = 1.237 m

    Length of CD

    Lcd = √(0.6² + 0.9² + (2.1 - 0.6)²)

    Lcd = 1.849 m

    Sum forces in the z direction to zero

    0 = (0.6 / Lad)Tad + (0.6 / Lbd)Tbd + (0.6 / Lcd)Tcd - 100

    0 = (0.6 / 1.723)Tad + (0.6 / 1.237)Tbd + (0.6 / 1.849)Tcd – 100

    0 = 0.3482Tad + 0.4851Tbd + 0.3244Tcd – 100

    Tad = (100 - 0.4851Tbd - 0.3244Tcd) / 0.3482

    Tad = 287.2 – 1.393Tbd – 0.9318Tcd

    Sum forces in the y direction to zero

    0 = ((2.1 – 0.6) / Lcd)Tcd - (0.6 / Lad)Tad – (0.6 / Lbd)Tbd

    0 = (1.5/1.849)Tcd - (0.6/1.723)Tad – (0.6/1.237)Tbd

    0 = 0.8112Tcd - 0.3482Tad – 0.4850Tbd

    Sub in Tad from above

    0 = 0.8112Tcd - 0.3482(287.2 – 1.393Tbd – 0.9318Tcd) – 0.4850Tbd

    0 = 0.8112Tcd - 100 + 0.4850Tbd + 0.3245Tcd – 0.4850Tbd

    0 = 1.1357Tcd - 100

    Tcd = 88 N <===ANS

    Tad = 287.2 – 1.393Tbd – 0.9318(88)

    Tad = 205.2 – 1.393Tbd

    Sum forces in the x direction to zero

    0 = ((2.4 – 0.9) / Lad)Tad – (0.9 / Lbd)Tbd – (0.9 / Lcd)Tcd

    0 = (1.5) / 1.723)Tad – (0.9 / 1.237)Tbd – (0.9 / 1.849)88

    0 = 0.8706Tad – 0.7276Tbd – 42.83

    0 = 0.8706(205.2 – 1.393Tbd) – 0.7276Tbd – 42.83

    0 = 178.64 – 1.2127Tbd – 0.7276Tbd – 42.83

    1.9403Tbd = 135.81

    Tbd = 70 N <===ANS

    Tad = 205.2 – 1.393(70)

    Tad = 108 N <===ANS

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