Anonymous
Anonymous asked in Science & MathematicsPhysics · 6 years ago

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• Whome
Lv 7
6 years ago

Lad = √(0.6² + 0.6² + (2.4 - 0.9)²)

Length of BD

Lbd = √(0.6² + 0.6² + 0.9²)

Lbd = 1.237 m

Length of CD

Lcd = √(0.6² + 0.9² + (2.1 - 0.6)²)

Lcd = 1.849 m

Sum forces in the z direction to zero

0 = (0.6 / Lad)Tad + (0.6 / Lbd)Tbd + (0.6 / Lcd)Tcd - 100

0 = (0.6 / 1.723)Tad + (0.6 / 1.237)Tbd + (0.6 / 1.849)Tcd – 100

0 = 0.3482Tad + 0.4851Tbd + 0.3244Tcd – 100

Tad = (100 - 0.4851Tbd - 0.3244Tcd) / 0.3482

Tad = 287.2 – 1.393Tbd – 0.9318Tcd

Sum forces in the y direction to zero

0 = ((2.1 – 0.6) / Lcd)Tcd - (0.6 / Lad)Tad – (0.6 / Lbd)Tbd

0 = (1.5/1.849)Tcd - (0.6/1.723)Tad – (0.6/1.237)Tbd

0 = 0.8112Tcd - 0.3482Tad – 0.4850Tbd

0 = 0.8112Tcd - 0.3482(287.2 – 1.393Tbd – 0.9318Tcd) – 0.4850Tbd

0 = 0.8112Tcd - 100 + 0.4850Tbd + 0.3245Tcd – 0.4850Tbd

0 = 1.1357Tcd - 100

Tcd = 88 N <===ANS

Tad = 287.2 – 1.393Tbd – 0.9318(88)

Sum forces in the x direction to zero

0 = ((2.4 – 0.9) / Lad)Tad – (0.9 / Lbd)Tbd – (0.9 / Lcd)Tcd

0 = (1.5) / 1.723)Tad – (0.9 / 1.237)Tbd – (0.9 / 1.849)88

0 = 0.8706Tad – 0.7276Tbd – 42.83

0 = 0.8706(205.2 – 1.393Tbd) – 0.7276Tbd – 42.83

0 = 178.64 – 1.2127Tbd – 0.7276Tbd – 42.83

1.9403Tbd = 135.81

Tbd = 70 N <===ANS