# A 2200/250V transformer takes 0.5A at a pf of 0.3 on open circuit. Find the magnetising and working components of no-load primary current.?

A 2200/250V transformer takes 0.5A at a pf of 0.3 on open circuit. Find the magnetising and working components of no-load primary current.

(with solution)

thanks

### 2 Answers

Relevance

- BrambleLv 75 years agoBest Answer
The magnetising component is 0.5 x 0.954 = 0.477 amps {note that : 0.954 = sin[arc-cos(0.3)]}

The working component is 0.5 x 0.3 = 0.15 amps

You don't seem very good at awarding Best Answer. I like to see some appreciation of the answerers' efforts to help you. So if you award this question I'll continue to another of yours.

- khalilLv 75 years ago
it is a resistor in parallel with an inductor

cos phi = 0.3 sin phi = 0.95

IR = 0.5 x 0.3 = 0.15 A

IL = 0.5 x 095 = 0.47 A

V / IR = 2200 / 0.15 >>>>>R = 14666 ohms

V / IL = 2200 / 0.47 >>>>Xl = 4680 ohms

Still have questions? Get your answers by asking now.