Solve for z, e ^ (iz) = -1?
r = sqrt ( (-1)^2 ) =1
theta = arctan (y/x) + pi sgn (y) = 0
I get z = 2(k)(pi), k is an integer.
I keep getting a wrong answer. Can anyone help
The correct answer is 2(k) pi + pi
- xyzzyLv 76 years agoFavorite Answer
e^&pi&i = -1
it is one of the beautiful equations in mathematics.
e^ix = cos x + i sin x
cos x = -1
x = (2n+1) π
θ = arctan (y/x) + 2n π is correct. I don't know why you have sgn (y) in your formula.
anyway.. with x = -1 draw it out and look at where θ has to be..