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# Solve for z, e ^ (iz) = -1?

r = sqrt ( (-1)^2 ) =1

theta = arctan (y/x) + pi sgn (y) = 0

I get z = 2(k)(pi), k is an integer.

I keep getting a wrong answer. Can anyone help

Update:

The correct answer is 2(k) pi + pi

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- xyzzyLv 76 years agoFavorite Answer
e^&pi&i = -1

it is one of the beautiful equations in mathematics.

e^ix = cos x + i sin x

cos x = -1

x = (2n+1) π

θ = arctan (y/x) + 2n π is correct. I don't know why you have sgn (y) in your formula.

anyway.. with x = -1 draw it out and look at where θ has to be..

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