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A chemical question
In an accident, some HCl was split out. Which of the following substances, when added in excess, would neutralize the acid without leaving any alkaline solution?
Why is the answer C?
- ?Lv 77 years agoFavorite Answer
The answer is : (C) CaCO3
NaOH can be used to neutralize HCl.
NaOH + HCl → NaCl + H2O
When NaOH is added in excess, a part of NaOH neutralizes the HCl. The unreacted NaOH will be left as an alkaline solution.
Lime water is Ca(OH)2 solution, which can be used to neutralize HCl.
Ca(OH)2 + 2HCl → CaCl2 + 2H2O
When limewater is added in excess, a part of Ca(OH)2 neutralizes the HCl. The unreacted Ca(OH)2 will be left as an alkaline solution.
CaCO3 can be used to neutralize HCl.
CaCO3 + 2HCl → CaCl2 + H2O + CO2
When CaCO3 is added in excess, a part of CaCO3 neutralizes the HCl. The unreacted CaCO3 solid is insoluble in water and thus no alkaline solution is left.
H2O can be used to dilute the HCl, but it cannot neutralize the HCl.Source(s): 土扁