Easy physics problem?!?!?
Boiled water that weighs 3kg is in an aluminium bowl that weighs 300g and the water has cooled to 17°C. How much heat was let free?
~I translated the problem, so it might not be written right, but it's correct.
I think I need to use the thermodynamic formula: m1c1(tf-t1)=m2c2(t2-tf)
Thanks from advance! :)
- ArjanLv 46 years agoFavorite Answer
You're looking in the right direction with those formulas.
with Q energy of the heat in Joule [J]
with m the mass of the object [kg]
with c the specific heat capacity in Joule per kilogramKelvin [J/(kg*K)]
with dT the temperature difference in Kelvin [K]
The temperature starts at 373 Kelvin (cause it's boiling) and it ends at 290 Kelvin (17°C)
so dT= 373-290=83
c is different for each material so you need to look this up:
c for water=4.2 J/(kg*K)
c for aluminium= 910 J/(kg*K)
Heat for the bowl:
Q=0.3*910*83= 22659 J
Heat for the water:
Total heat: 22659+1045,8=23704,8 J