Pre calc graphing help?

Question

How do you solve this

Find the domain, range, asymptote of the following functions

1). y= e^-3x. +1

2). y=log (x+2)

Answer 1

1) Domain: x=all real numbers

Range: y=(1,infinity)

Asymptote: y=1 (b/c the parent graph has been shifted up by 1 unit).

2) Domain: x=(-2,infinity)

Range: y=all real numbers

Asymptote: x=-2 (b/c the parent graph has been shifted to the left by 2 units)

Answer 2

Anurag gave you the answer to the problem.

Your question is "How do you solve it?"

You have to be familiar with the exponential function f(x) = e^x and the logarithmic function g(x) = log x. (I am assuming "log x" means log "base 10" x. However the answer is the same either way.)

The exponential function, f(x), has a domain of all real numbers and a range of all positive real numbers.

The logarithmic function, g(x), is the inverse function to f(x) and the domain of f(x) is the range of g(x) and vice versa.

Know the definition of an asymptote is a straight line that a function approaches but never quite reaches.