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# solve the following problem?

if (x-2) is a factor of x^3 +ax^2 + bx + 16 and b= 4a then find the values of a and b.

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- davidLv 77 years ago
if (x-2) is a factor of x^3 +ax^2 + bx + 16 and b= 4a then find the values of a and b.

f(2) = 8 +4a + 2b + 16 = 0

4a + 2b = -24 ... sub b = 4a

4a + 8a = -24

a = -2

b = -8

- ?Lv 77 years ago
if (x - 2) is a factor, then f(2) = 0

f(2) = (2)^3 + a(2)^2 + 4a(2) + 16 = 0

8 + 4a + 8a + 16 = 0

12a = - 24

a = - 2

b = - 8

check...I did

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