Finding centripetal acceleration?
We had to make a graph of period squared versus mass and were given the formula of t^2=(4pi^2r/ac)m and from this equation we use our slope (0.52) to find the centripetal acceleration. I think I am over thinking this problem, but I can not figure out how to solve this.
- WoodsmanLv 76 years agoBest Answer
a = ω²r = 4π²r/T² rearranges to T² = 4π²r / a
I don't know how you wiggled the mass into this equation.
You have kg on the RHS, but not on the LHS.
(I'm assuming your "ac" is acceleration, units m/s².)
Is it possible you plotted T² vs the radius r?
Then the slope = 0.52 = 4π² / a
and you can easily solve for a.
If you can elaborate, I'll have another look.