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Rbgrijó
Lv 7
As raízes da equação ax²+bx+1=0, são x' e x'' com x'>x'', se Delta=2, então 1/x'' - 1/x' vale?
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- LucasLv 77 years agoFavorite Answer
Olá.
x'-x'' = VD/ a, x'.x''=c/a
1/x'' - 1/x' =
x'-x'' / x'''.x'
VD/a / c/a
VD/a . a/c
VD /c
√2 /1
√2
--------
Até !
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