Prove that if N is a normal subgroup of G then the multiplication on G/N given by aN*bN = abN is well defined?

Prove that if N is a normal subgroup of G then the multiplication on G/N given by aN*bN = abN is well defined

1 Answer

Relevance
  • 6 years ago
    Favorite Answer

    Since N is normal bNb^-1 = N ==> aNbN = a(bNb^-1)(bN) = abN(b^-1b)N = abN1N = abN.

Still have questions? Get your answers by asking now.