# Please help Physics!!?

The total mass of the hydrogen gas in the Hindenburg zeppelin was 18,000 kg. Assuming standard conditions, what volume did the hydrogen occupy?

### 3 Answers

Relevance

- WhomeLv 76 years agoBest Answer
density of hydrogen at stp is

ρ = 0.0899 kg/m³

V = m / ρ

V = 18000 / 0.0899

V = 200(10³) m³

- 6 years ago
Formula for volume of a circle. 2Pi*r, so you need the radius of the Hindenburg's tank.

- Big DaddyLv 76 years ago
Molecular weight of H2 is 2.0159 g/mol

mw = m/n

n = m/mw

n = 18000kg / (2.0159g/mol)

n = 8.929x10^6mol

At STP, one mole of gas has a volume of 22.4L

V = n * 22.4L/mol

V = 8.929x10^6mol * 22.4L/mol

V = 2.00x10^8l = 2.00x10^5 m^3

Still have questions? Get your answers by asking now.