ATH asked in Science & MathematicsPhysics · 7 years ago

How far apart are the two conducting plates if their potential difference is 0.14 kV in m?

Suppose the electric field between two conducting plates has a strength of 43 × 103 V/m.

1 Answer

  • 7 years ago
    Favorite Answer

    The field strength is given as 43.0^3V/m (43.0kV/m)

    So .. a pd of 1.0kV corresponds to a distance (1/43)m along the field lines.

    0.14kV corresponds to a distance 0.14 x (1/43)m .. .. ►d = 0.0033m

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