How far apart are the two conducting plates if their potential difference is 0.14 kV in m?
Suppose the electric field between two conducting plates has a strength of 43 × 103 V/m.
- JullyWumLv 77 years agoFavorite Answer
The field strength is given as 43.0^3V/m (43.0kV/m)
So .. a pd of 1.0kV corresponds to a distance (1/43)m along the field lines.
0.14kV corresponds to a distance 0.14 x (1/43)m .. .. ►d = 0.0033m