Anonymous

# Why does the C parameter in standard form not equal the k parameter in vertex form?

Why does the "c" parameter in standard form, f(x) = ax^2 + bx + c, not equal the "k" parameter in vertex form, y= a (x-h) ^2 ?

Provide a mathematical argument based on algebraic work.

### 1 Answer

Relevance

- BeeFreeLv 76 years agoFavorite Answer
Emily

Here is a simple argument .... assuming a, h and k are all non-zero:

STANDARD FORM:

f(x) = ax^2 + bx + c

f(0) = c

VERTEX FORM:

f(x) = a (x-h) ^2 + k

f(0) = ah^2 + k

You should now see that ...

f(0) = c = ah^2 + k

c ≠ k unless h = 0

Hope that helps

Still have questions? Get your answers by asking now.