Its a math question and its really hard.?
A surveyor starting from a point A moves N 35° E a distance of 651′ to point B. Next, she moves N 56° E a distance of 439′ to point C. Next, she walks S 8° W a distance of 1619′ to point D. Finally, she returns to the starting point.
What distance must she walk to return to the starting point? (Answer accurate to the nearest foot.)
What heading does she walk from the fourth point to return to the starting point? (Answer accurate to the nearest degree.)
N. _° W
What is the size of this plot of land?
area = square feet
- tcLv 77 years agoFavorite Answer
AP = 651cos 55 = 373.4
BP = 651sin 55 = 533.3
PQ = 439cos 34 = 364
CS = 439sin 34 = 245.5
AQ = AP+PQ = 737.4
CQ = CS+BP = 778.8
CT = 1619cos 8 = 1603.2
DT 1619sin 8 = 225.3
QT = CT-CQ = 824.4 = AR
RD = AQ-DT = 512.1
AD = 970.5 => by pythagorean theorem
<ADR = tan^-1(824.4 / 512.1) = 58.15
90-58.15 = 31.85
the area = UCTR - out area =>please try do it.
hope not make any mistake.