can i not balance the reaction of hydrolysis of XeF4 like this : 4XeF4 + 8H2O gives 2Xe + 2XeO3 + 16HF + O2?
- BIILv 76 years agoFavorite Answer
You have indeed balanced an equation for the hydrolysis of XeF4, but an equation that presumably more accurately reflects the stoichiometry of the rxn is:
6XeF4 + 12H2O → 4Xe + 2XeO3 + 24HF + 3O2
Adapted from the eqn that has fractional coefficients given in
N. N. Greenwood, A. Earnshaw, Chemistry of the Elements 2nd ed. (1997) p 896
'It [XeF4] is also hydrolysed instantly by water, yielding a variety of products which include XeO3."