Jane and John, with masses of 49 kg and 66 kg, respectively, stand on a frictionless surface 15 m apart. John?
Jane and John, with masses of 49 kg and 66 kg, respectively, stand on a frictionless surface 15 m apart. John pulls on a connecting rope, giving Jane an acceleration of 1.5 m/s2 toward him. If the pulling force is applied constantly, how far Jane has travelled when they meet?
I am having so many issues with this question. My answer is 5.74 but idk if thats right
- WoodsmanLv 77 years agoFavorite Answer
Jane has less mass so must move farther than John, since their center of mass does not move. The accelerations/forces aren't relevant.
49kg * x = 66kg * (15m - x) where x is the distance from Jane to the center of mass.
49x = 990 - 66x
115x = 990
x = 8.6 m