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# Jane and John, with masses of 49 kg and 66 kg, respectively, stand on a frictionless surface 15 m apart. John?

Jane and John, with masses of 49 kg and 66 kg, respectively, stand on a frictionless surface 15 m apart. John pulls on a connecting rope, giving Jane an acceleration of 1.5 m/s2 toward him. If the pulling force is applied constantly, how far Jane has travelled when they meet?

I am having so many issues with this question. My answer is 5.74 but idk if thats right

### 1 Answer

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- WoodsmanLv 77 years agoFavorite Answer
Jane has less mass so must move farther than John, since their center of mass does not move. The accelerations/forces aren't relevant.

49kg * x = 66kg * (15m - x) where x is the distance from Jane to the center of mass.

49x = 990 - 66x

115x = 990

x = 8.6 m

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