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# if 3 meters cube of a gas initially at stp is placed under a pressure of 4.00 atm the temperature of the gas?

if 3 meters cube of a gas initially at stp is placed under a pressure of 4.00 atm the temperature of the gas rises to 38 degree celsius what is the volume?

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- Anonymous6 years agoFavorite Answer
Go back to the lesson on "combined gas law" and learn it. You need to know that perfectly. It is entirely expressed in one equation:

PV = NRT where

P = Pressure

V = Volume

N= quantity of gas

R = a constant depending on what units you want to use

T = absolute temperature.

So you are given P = 1, V = 3, T = 25. You have to convert T to absolute, so you add 273.15 and get 298.15C

1 x 3/298.15 = NR and NR is constant (we do not change the quantity of gas or the gas constant). So we can set that equal to the new conditions:

3/298.15 = 4V/311.15

V = 0.7827 m^3

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