if 3 meters cube of a gas initially at stp is placed under a pressure of 4.00 atm the temperature of the gas?
if 3 meters cube of a gas initially at stp is placed under a pressure of 4.00 atm the temperature of the gas rises to 38 degree celsius what is the volume?
- Anonymous6 years agoFavorite Answer
Go back to the lesson on "combined gas law" and learn it. You need to know that perfectly. It is entirely expressed in one equation:
PV = NRT where
P = Pressure
V = Volume
N= quantity of gas
R = a constant depending on what units you want to use
T = absolute temperature.
So you are given P = 1, V = 3, T = 25. You have to convert T to absolute, so you add 273.15 and get 298.15C
1 x 3/298.15 = NR and NR is constant (we do not change the quantity of gas or the gas constant). So we can set that equal to the new conditions:
3/298.15 = 4V/311.15
V = 0.7827 m^3