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# Please help me with a math problem?

according to statistics canada, Chestermere, Alberta is one of the fastest growing communities in canada. between 2001 to 2006, the population grew an average rate of about 8 percent per year.

(A) the population of Chestermere in 2001 was 6462. Determine the population for the years 2002 to 2004, inclusive.

(B) write a general term of the geometric sequence that models the population of Chestermere, where n is the number of years starting in 2001.

(C) predict the population if Chestermere in 2020

Please help

Thank you so much!

### 2 Answers

- M3Lv 78 years agoFavorite Answer
qa

2002: 6462*1.08 = 6979

2003: 6462*1.08^2 = 7537

2004: 6462*1.08^3 = 8140

qb

6462*1.08^n

qc

6462*1.08^19 = 27,888 <------

- 8 years ago
A) If the growth rate is 8 percent each year, then the population is equal to the previous years total multiplied by 1.08. For example in the year 2002, the population would equal the population in 2001 (6462) times 1.08, so 2002 population = 6462*1.08 = 6978.96 = 6979

B) A geometric sequence follows the rule t(n) = ar^(n-1), where a is the starting value and r is the common ratio. In this case a = 6462, r = 1.08 and n = year - 2001

t(n) = 6462*1.08^(n-1)

C) Using the above general term, the population in 2020 can be calculated by substituting (2020 - 2001) as n into the formula.