An electric field of 420000 N/C points due west at a certain spot. What is the magnitude of the force that act?

Update:

-9.7Micro C

1 Answer

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  • 6 years ago
    Best Answer

    You are missing the value of the charge.

    For example if the question is

    "An electric field of 420000 N/C points due west at a certain spot. What is the magnitude of the force that acts on a -3microC charge at this spot?

    F = qE = (-3x10^-6) x 420000 = -1.26N

    If the field's direction (west) is taken as positive, the negative answer means the force is east. So the answer would be 1.26N due east.

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