I have a intro to Engineering questions?

The fluid in a cup sitting on the surface of a table exerts a force on the table given by the equations:

F=pgV

Where p represents the fluid density, g the acceleration due to gravity, and V the volume of the fluid. In terms of the fundamental dimensions [L,M,t] what is the dimension of the right hand side of the equation. What is the dimension of the force F (F=ma)?

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  • 6 years ago
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    LHS:

    F=m.a

    =kg. m/s2

    =ML/T2

    RHS:

    rho=kg/m3

    g =m/s2

    V=m3

    Multiplying these,

    F=kg.m/s2

    =ML/T2

    Thus, RHS=LHS

    Hence the proof!

    Source(s): Self
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