# I have a intro to Engineering questions?

The fluid in a cup sitting on the surface of a table exerts a force on the table given by the equations:

F=pgV

Where p represents the fluid density, g the acceleration due to gravity, and V the volume of the fluid. In terms of the fundamental dimensions [L,M,t] what is the dimension of the right hand side of the equation. What is the dimension of the force F (F=ma)?

### 1 Answer

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- 6 years agoFavorite Answer
LHS:

F=m.a

=kg. m/s2

=ML/T2

RHS:

rho=kg/m3

g =m/s2

V=m3

Multiplying these,

F=kg.m/s2

=ML/T2

Thus, RHS=LHS

Hence the proof!

Source(s): Self

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