A sound wave ahs frequency 500 Hz and velocity 360 m/sec. what is the distance between two particles having ph?

A sound wave ahs frequency 500 Hz and velocity 360

m/sec. what is the distance between two particles

having phase difference of 60??

(a) 0.7 cm

(b) 12.0 cm

(c) 70 cm

(d) 120.0 cm

show the work plz..

2 Answers

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  • 8 years ago
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    λ=v/f = 360/500= 0.72m

    phase difference 60deg. = 0.72*60/360= 0.12m = 12[cm] (b)

  • 8 years ago

    Equation of a waveform:

    Velocity = wavelength * frequency

    Therefore, wavelength = velocity/frequency

    wavelength = 360m/s / 500/s = 0.72 m = 70 cm

    (This solution is applicable for Introductory Physics)

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