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# A sound wave ahs frequency 500 Hz and velocity 360 m/sec. what is the distance between two particles having ph?

A sound wave ahs frequency 500 Hz and velocity 360

m/sec. what is the distance between two particles

having phase difference of 60??

(a) 0.7 cm

(b) 12.0 cm

(c) 70 cm

(d) 120.0 cm

show the work plz..

### 2 Answers

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- Masked_Rider1101Lv 78 years agoFavorite Answer
λ=v/f = 360/500= 0.72m

phase difference 60deg. = 0.72*60/360= 0.12m = 12[cm] (b)

- 8 years ago
Equation of a waveform:

Velocity = wavelength * frequency

Therefore, wavelength = velocity/frequency

wavelength = 360m/s / 500/s = 0.72 m = 70 cm

(This solution is applicable for Introductory Physics)

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