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# SOLVE THE FOLLOWING PROBLEM?

SOLVE THE FOLLOWING PROBLEM?

IF 3+√7/3-√7 + 3-√7/3+√7 = a+b√7 , FIND THE VALUE OF a AND b .

PLZ SOLVE THIS

### 2 Answers

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- steiner1745Lv 78 years agoFavorite Answer
I'll assume you mean

(3+√7)/(3-√7) + (3-√7)/(3+√7)

Just combine the fractions to get

1/2[(3+√7)^2 + (3-√7)^2] =

1/2*(9+7+9+7+6√7 - 6√7) =

1/2*(32) = 16.

So a = 16, b = 0.

- 8 years ago
If you mean this...: (3+√7/3) - (√7+3-√7/3) + (√7) = a + b√7

Solution:

(3+√7/3) - (√7+3-√7/3) + (√7) = a + b√7

((1) + (√7/3)) - ((√7/3) + (1) - (√7/3)) + (√7) = a + b√7

(1) + (√7/3) - (√7/3) + (1) - (√7/3) + (√7) = a + b√7

2 - √7/3 + √7 = a + b√7

2(3) - √7/3(3) + √7(3) = a + b√7

6 - √7 + 3√7 = a + b√7

6 + 2√7 = a + b√7

So,

a = 6

b = 2

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