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# Really hard critical thjnkingmath?

Jerry is three times as old as brian. Five years ago the sum of their ages was 34. Find their ages now?

### 3 Answers

- Anonymous7 years agoFavorite Answer
J= 3B

J-5 + B -5 = 34

Use system of equations, substitution . Plug in J into everywhere you see J in the second equation.

3B-5 + B -5= 34

4B= 44

B= 11.....Plug B into first equation to find J

J= 3(11)

J= 33

Jerry is 33 years old while Brian is 11

CHECK: 33/11 is 3 times as old. Five years ago. 28 and 6. 28+6 = 34...Correct!

Hope this helped a lot!

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Source(s): Grade 11 maths - answerINGLv 67 years ago
Jerry is currently 33; Brian is 11.

The equation(s) for the problem could be:

J = 3B, where J is Jerry's age now; B is Brian's age now.

J -5 + B-5 =34 so (substituting) 3B -5 + B-5 =34;

solving for B gives B =11, etc.

- 7 years ago
J = 3B. (J-5) + (B-5) = 34. So 4B = 44 => B = 11 => J = 33. So Jerry is 33, and Brian is 11.