Really hard critical thjnkingmath?
Jerry is three times as old as brian. Five years ago the sum of their ages was 34. Find their ages now?
- Anonymous7 years agoFavorite Answer
J-5 + B -5 = 34
Use system of equations, substitution . Plug in J into everywhere you see J in the second equation.
3B-5 + B -5= 34
B= 11.....Plug B into first equation to find J
Jerry is 33 years old while Brian is 11
CHECK: 33/11 is 3 times as old. Five years ago. 28 and 6. 28+6 = 34...Correct!
Hope this helped a lot!
.Source(s): Grade 11 maths
- answerINGLv 67 years ago
Jerry is currently 33; Brian is 11.
The equation(s) for the problem could be:
J = 3B, where J is Jerry's age now; B is Brian's age now.
J -5 + B-5 =34 so (substituting) 3B -5 + B-5 =34;
solving for B gives B =11, etc.
- 7 years ago
J = 3B. (J-5) + (B-5) = 34. So 4B = 44 => B = 11 => J = 33. So Jerry is 33, and Brian is 11.