Really hard critical thjnkingmath?

Jerry is three times as old as brian. Five years ago the sum of their ages was 34. Find their ages now?

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  • Anonymous
    7 years ago
    Favorite Answer

    J= 3B

    J-5 + B -5 = 34

    Use system of equations, substitution . Plug in J into everywhere you see J in the second equation.

    3B-5 + B -5= 34

    4B= 44

    B= 11.....Plug B into first equation to find J

    J= 3(11)

    J= 33

    Jerry is 33 years old while Brian is 11

    CHECK: 33/11 is 3 times as old. Five years ago. 28 and 6. 28+6 = 34...Correct!

    Hope this helped a lot!

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    Source(s): Grade 11 maths
  • 7 years ago

    Jerry is currently 33; Brian is 11.

    The equation(s) for the problem could be:

    J = 3B, where J is Jerry's age now; B is Brian's age now.

    J -5 + B-5 =34 so (substituting) 3B -5 + B-5 =34;

    solving for B gives B =11, etc.

  • 7 years ago

    J = 3B. (J-5) + (B-5) = 34. So 4B = 44 => B = 11 => J = 33. So Jerry is 33, and Brian is 11.

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