Can someone help with chemistry?
From the following reactions:
CH3OH + (3/2)O2 ----> CO2 + 2H2O .... DeltaH = -726 kj/mol
C + O2 ---> CO2 ... DeltaH = -393.5 kj/mol
H2 + (1/2)O2 ----> H2O ... DeltaH = -285.5 kj/mol
Calculate the DeltaH for the following reaction:
C + 2H2 + (1/2)O2 ---> CH3OH
answer DeltaH= _____kl
- 7 years agoFavorite Answer
For this problem, you need to manipulate the first and third equations. Flip the first one around (which makes the delta H positive) and multiply the third equation by two. After lining them back up again, you see that all of the reaction intermediates cancel out and you are left with a delta H of -232.5 kJ/mol.