Can someone help with chemistry?

From the following reactions:

CH3OH + (3/2)O2 ----> CO2 + 2H2O .... DeltaH = -726 kj/mol

C + O2 ---> CO2 ... DeltaH = -393.5 kj/mol

H2 + (1/2)O2 ----> H2O ... DeltaH = -285.5 kj/mol

Calculate the DeltaH for the following reaction:

C + 2H2 + (1/2)O2 ---> CH3OH

answer DeltaH= _____kl

1 Answer

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  • 7 years ago
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    For this problem, you need to manipulate the first and third equations. Flip the first one around (which makes the delta H positive) and multiply the third equation by two. After lining them back up again, you see that all of the reaction intermediates cancel out and you are left with a delta H of -232.5 kJ/mol.

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