# help electronics logic gates?

Ā.B.C --> NOT -->Q

A. B(bar).C ---->NOT --> R

Q+R--->NOR ---> P

P?

### 1 Answer

Relevance

- Anonymous6 years agoFavorite Answer
Ā.B.C --> NOT-->(A'BC)'-->Q

A. B(bar).C ---->NOT-->(AB'C)'-->R

Q+R=(A'BC)'+(AB'C)'

=A+B'+C'+A'+B+C' [De Morgans law]

=(A+A')+(B+B')+C'+C'

=1+1+C'+C' [[COMPLEMENTARY LAW]]

=1+C' [IDEMPOTENCE LAW]

=1 [PROPERTIES OF 1]

SO P=1

Still have questions? Get your answers by asking now.