Evaluate the limit. if the limit does not exist explain why. a) lim[x:(-2),(x^3+8)/(x+2)]?
it would help a lot if you guy can show the work so i can learn how to do it! thank
- 7 years agoFavorite Answer
for problems of the type 0/0 or inf/inf, one uses a concept call L'Hopital's rule in order to simplify the equation. Look it up on wikipedia
a) with x : -2, the equation reduces to the form 0/0. Hence you can use L'Hopital's rule.
Differentiating numerator and denominator, w.r.t. x
required limit = lim [x:-2], 3x^2 = 3(-2)^2 = 12
b) this is again of the form 0/0, so differentiate w.r.t x, which means required limit = 1
c) this one is of the form 1/0 so you cannot use the rule. The limit in this case is "infinity"Source(s): Graduate in Applied Physics
- 4 years ago
factor the denominator (x^3+8) utilising sum of ideal cubes and then component to it is going to cancel with the numerator (x+2). Then stick in -2 everywhere you spot an x and notice what it provides. this could be your answer.
- grunfeldLv 77 years ago
a) = lim ( x -- > - 2 ) 3x^2
c) DNESource(s): my brain
- 7 years ago