# Please try solving this equation for me?

The number of boys and girls in a class are in the ratio 7:5. The number of boys is 8 more than number of girls. What is the total class strength?

P.S use one variable only

Relevance

Total strength = 48

Boys = 28

Girls = 20

Ratio Boys:Girls as given 7:5

I know my answer is correct, but please don't expect from me such answers in future. Also don't ask for work sheet. I deserve full marks. What you say no. No matter agreed.

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Thank you.

Source(s): ever feel
• Assuming the ratio means 7 boys to 5 girls, you would solve this by the equation:

7x=5x+8 (You want to find a common multiple that will give you a result where 8 more girls will equal the number of boys.)

7x-5x=8

2x=8

x=4 (This will be your multiplyer.)

The ratio then becomes 28 boys:20 girls. Then add: 28+20=48.

Class size would be 48.

Source(s): I have a job where I do this kind of math every day
• boys 7 girls 5 8 more boys than girls

7x= 5x+8

2x=8 x=4 28 boys and 20 girls 20/48 reduced is 5/12 28/48=7/12 x=4

• 7+5 = 13 kids

7-5 = 2 more boys

8/2 =4

therefore 13*4 = 52

• This is how it should be done.

B ⁄ G = 7 ⁄ 5

5B = 7G

B = 7G ⁄ 5 ... equation 1

B = G + 8 ... equation 2

7G ⁄ 5 = G + 8 ... substituted for B using eq.1

7G ⁄ 5 = (5G ⁄ 5) + 8

2G ⁄ 5 = 8

G = 20 ... number of girls

B = G + 8 ... eq.2

B = 20 + 8

B = 28 ... number of boys

Total = B + G  =  28 + 20  =  48

• 7x + 2 = 3x - 2 ... circulate all components to a minimum of one area, replace sign in case you progression it to different area of "=" > 7x + 2 - 3x + 2 = 0 > 7x - 3x + 2 + 2 = 0 > 4x + 4 = 0 > 4x = - 4 > 4x/4 = -4/4 ... dividing the two sides via 4 > 1x = -a million > x = -a million/a million > x = -a million

• 1875 lbs

Source(s): 25 kids 75lbs each