PLEASE HELP!!! pK (= −log K) at 25°C?

What is the pK (= −log K) at 25°C for the reaction below?

2 ClO3−(aq) + 12 H+(aq) + 5 Ba(s) « Cl2(g) + 6 H2O(l) + 5 Ba2+(aq) E° = 4.370 V.

I have no clue how to do this please show me how I give best answer!!!

Thank you

Update:

I have no idea what the person below wrote but the answer is....-738.2 I don't know how to get it though

1 Answer

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  • Anonymous
    7 years ago
    Favorite Answer

    K=10^(16,903x10x4,370)=10^738,7

    pK=-log(10^738,7)=738,7

    n is the number of electrons and it is 10 because to take the reaction above you multiply x5 the reduction half reaction of Ba.

    Let me know if you understood it.

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