How much CO2 needed to make octane?
Balanced: 16CO2(g) +18H2O(l) 2C8H18(l) +25O2(g)
1 gallon of gas weighs 3700 g. From the balanced reaction, find out how many moles of CO2 are needed to make that many moles of octane, which is a gallon of gas.
- Roger the MoleLv 77 years agoFavorite Answer
(3700 g C8H18) / (114.22929 g C8H18/mol) x (16 mol CO2 / 2 mol C8H18) x
(44.00964 g CO2/mol) = 11400 g CO2
(Although it is difficult to imagine any conditions under which this reaction would actually occur. In fact the arrow of that reaction points to the left.)