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# What is 2 over n-3 + 6 over n^2-9n+18=?

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- az_lenderLv 77 years agoFavorite Answer
This can be correctly written as

2/(n-3) + 6/(n^2-9n+18).

Read the Wikipedia article entitled "Order of Operations"

Anyway, since n^2-9n+18 = (n-3)(n-6), you use that as a common denominator:

2(n-6) / (n^2-9n+18) + 6/(n^2-9n+18)

= (2n-12+6) / (n^2-9n+18)

= (2n - 6) / (n^2 - 9n + 18).

This can't be "reduced" ...because (n-3) isn't a factor of n^2-9n+18.

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