What is 2 over n-3 + 6 over n^2-9n+18=?
- az_lenderLv 77 years agoFavorite Answer
This can be correctly written as
2/(n-3) + 6/(n^2-9n+18).
Read the Wikipedia article entitled "Order of Operations"
Anyway, since n^2-9n+18 = (n-3)(n-6), you use that as a common denominator:
2(n-6) / (n^2-9n+18) + 6/(n^2-9n+18)
= (2n-12+6) / (n^2-9n+18)
= (2n - 6) / (n^2 - 9n + 18).
This can't be "reduced" ...because (n-3) isn't a factor of n^2-9n+18.