Anonymous
Anonymous asked in Education & ReferenceHomework Help · 8 years ago

i need to solve the linear system of equations by computing X= A^-1 B

this has to be a matrix thats 2 by 2 and then the solution as well

x+6y=8

-6x+2y=28

Relevance
• I did matrix last year so it might be a bit rusty but I'll try my best!

so, the first matrix would be

[1 6] (first row )

[-6 2] (second row)

and the second matrix is

[x]

[y]

but pretend those are connected.. like, vertically.

and those 2 multiplied by each other equals

[ 8 ]



so you've got

[1 6]*[x]=[ 8 ]

[-6 2] [y] 

the first matrix is "A" so you raise that to the first power

and the third matrix is your "B"

so then you put them back into the equation X=A^-1 B

thuss,

[1 6]^-1 *  = [x]

[-6 2] ..... .[y]

make sure you raise the whole matrix to the negative one power and not just [1 6]

Hope it helped? I'm a junior in high school so yeah...

Source(s): high school math..
• Anonymous
8 years ago

x=-6y+8

substitute

-6(6y+8)+2y=28

solve for y

substitute into one of the equations