Anonymous
Anonymous asked in Science & MathematicsChemistry · 7 years ago

# what is the pH of 0.025 M NaOH solution?

A) 12.40

B) 1.60

C) 11.50

D) 2.50

Also, if you wouldn't mind explaining how you figure it out that would be great! Thanks :)

Relevance
• 7 years ago

Not sure what chemistry you are currently in, but it is pretty plain and simple. .025 M is your concentration of NaOH. So just take the -log of that concentration. Since NaOH is a base, you will end up with the pOH. Then, plug that value into this equation 14=pH+pOH. Also, with it being a base, it should be above 7.

• 7 years ago

This is base

pOH= -log[OH-]

=-log[0.025]

=1.60

pH=14.00-pOh

= 14.00-1.60

= 12.40

Source(s): chemistry student
• 7 years ago

NaOH ---> Na+ + OH-

[OH-]= 0.025 M

pH =14 -( -log 0.025 )= 12.40

• 4 years ago

PH = -log[H3O+] four.93= -log[H3O+] --->log principles----> [H3O+]=10^-four.93 count on, based on the balanced equation HZ(aq) + H2O(l) <-----> H3O+(aq) + Z- (aq), that [H3O+]=[Z-] at equilibrium. Then, Ka = [products]/[reactants] = [H3O+][z-]/[HZ] = [H3O]^2/[HZ] = (1.A hundred seventy five x 10^-5)^2/zero.02 The reply is: 6.9 x 10^-9

• 7 years ago

pOH = - log(0.025)

pOH = - (-1.602)

pOH = 1.602

pH + pOH = 14

pH + 1.602 = 14

pH = 14 - 1.602

pH = 12.4