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# Please help me solve: (1/8-1/y)/(8-y/8)?

I know that when you divide by a fraction you actually multiply by its reciprocal but then I am lost. I need a common denominator, which is 8-y, but do I multiply each term by 8-y or do I just pick the parts that are missing? I am confused!! Thanks for any help.

(1/8-1/y)/(8-y/8)=

(1/8-1/y)(8/8-y)=?

### 1 Answer

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- 8 years agoFavorite Answer
(1/8 - 1/y) / ((8 - y) / 8) =>

(y - 8) * 8 / (8y * (8 - y)) =>

-8 / (8y) =>

-1/y

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