Can you find the inverse of each function(using logs)?

a) y=log base 2(x-3)

b) y=log base 2((1/3)x)+10

c) y=3^x

d) 2^x +7

Thank you so so much!!!

I will select a best answer :)

1 Answer

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    To find any inverse, switch x with y, then solve for y

    x = log[2](y - 3)

    2^x = y - 3

    3 + 2^x = y

    x = log[2](y/3) + 10

    x - 10 = log[2](y/3)

    2^(x - 10) = y/3

    3 * 2^(x - 10) = y

    x = 3^y

    ln(x) = y * ln(3)

    y = ln(x) / ln(3)

    y = log[3](x)

    x = 2^(y) + 7

    x - 7 = 2^y

    y * ln(2) = ln(x - 7)

    y = log[2](x - 7)

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