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# Can you find the inverse of each function(using logs)?

a) y=log base 2(x-3)

b) y=log base 2((1/3)x)+10

c) y=3^x

d) 2^x +7

Thank you so so much!!!

I will select a best answer :)

### 1 Answer

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- 7 years agoFavorite Answer
To find any inverse, switch x with y, then solve for y

x = log[2](y - 3)

2^x = y - 3

3 + 2^x = y

x = log[2](y/3) + 10

x - 10 = log[2](y/3)

2^(x - 10) = y/3

3 * 2^(x - 10) = y

x = 3^y

ln(x) = y * ln(3)

y = ln(x) / ln(3)

y = log[3](x)

x = 2^(y) + 7

x - 7 = 2^y

y * ln(2) = ln(x - 7)

y = log[2](x - 7)

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