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# How to factor this equation?

Please factor: 5n^3-18n^2-8

and if possible please solve this

5n^3-18n^2-8 divided by n-2

5n^3-18n^2-8 / n-2

### 1 Answer

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- RogueLv 77 years agoFavorite Answer
5n^3 - 18n^2 - 8 doesn't have rational factors

n - 2 ) 5n^3 - 18n^2 - 8

5n^2(n - 2) = 5n^3 - 10n^2

5n^3 - 18n^2 - ( 5n^3 - 10n^2 ) = -8n^2

-8n(n - 2) = -8n^2 + 16n

-8n^2 + 0n - ( -8n^2 + 16n) = 16n

16(n -2) = 16n - 32

=> 16n - 8 - ( 16n - 32 ) = 24

=> 5n^3-18n^2-8 / n-2 = 5n^2 - 8n + 16 + 24/(n -2)

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