# A card is drawn from a deck of 52 cards, find the probability of drawing .?

1) A red king

2) A jack, queen or Ace

3) A card which is neither a fade nor a king

4) A heart or a diamond

5) Either a black face card or a red ace's

6) A spade or a face card

### 12 Answers

- Anonymous7 years agoFavorite Answer
In a deck there a 52 cards with 4 suits(hearts,spades,diamonds and clovers). 2 suits are red while the other 2 are black. And there are 4 cards for each number.(ace,jack.queen etc.)And remember an ace isnt considered a face card.

1) there are 2 red kings in any given deck so probability is 2/52=1/26

2)since there are 4 cards of each

you multiply 4*3=12

probability is 12/52=3/13

3)I have no idea what a fade is.

4)Remember that there are 4 suits? Each suit has 13 cards.

So as there are 2 suits probability is 13*2/52=26/52=1/2

5)There are 26 black cards,and they contain 6 face cards. And there are 26 red cards which contain only 2 red aces. so add both 8/52=2/13

6)In a deck there are 12 face cards (king, queen, and jack) and 13 cards of spades

3 face cards are already in spades so subtract 3.

(9+13)/52=22/52=11/26

- jcherry_99Lv 77 years ago
1]

There are 2 red kings. 2/52 = 1/26

2]

There are 4 jacks, 4 queens and 4 aces.

12/52 = 3/13

3]

I'm taking fade to equal spade, but I guess it could be face. I'll do both.

spades

======

The easiest way to do this is to figure out the true statement and subtract that result from 1.

There are 13 spades and 3 other kings.

13/52 + 3/52 = 16/52 = 4/13

1 - 4/13 = 9/13

So you have a 9 out of 13 chance of drawing neither a spade of a king.

face

===

A king is included in the face cards. There are 12 face cards.

You can draw 12/52 face cards, so there are 40/52 ways of not drawing a face card.

20/26 = 10 /13

4]

There are 13 hearts or 13 diamonds. That's 26 cards all together.

26/52 = 1/2

5]

There are 6 black face cards and 2 red aces.

8 cards that you could draw that would give you a "win."

8/52 = 2/13

6]

There are 13 spades and 9 other face cards that are not spades. Don't forget, 3 spades are face cards and you cannot count them twice.

22 cards will give you success.

22/52 = 11/26

- JaredLv 77 years ago
1) There are two red kings: 2/52 = 1/26

2) There are 4 jacks, 4 queens, and 4 aces: 12/52 = 3/13

3) spade??? There are 13 spades, and 4 kings (one of which is a spade): there are 13 + 3 = 16 cards which are spades or kings: 1 - 16/52 = 1 - 4/13 = 9/13

4) there are 13 hearts and 13 diamonds: 26/52 = 1/2

5) There are 4 face cards (jack, queen, king, ace), so there are 2 * 4 = 8 black face cards, also there are 2 red aces (diamond and hearts): 8 + 2 = 10 --> 10/52 = 5/26

6) There are 4 face cards (see above) times 4 suits = 16 face cards. There are 13 spades, but FOUR of them are ALSO face cards, so there are 13 + 12 = 25 face cards or spades: 25/52

Edit:

It depends on what a face card is. If a "face card" means only jack, queen, king, then what I said above is wrong. Generally though, I consider an Ace to be a "face card" (when it comes to mathematicians that is probably not correct).

Assuming that Ace isn't a face card, then:

5) 3 face cards (jack, queen, king) times 2 black suits or the two red aces (either ace of hearts of ace of diamonds): 3 * 2 + 2 = 8: 8/52 = 2/13

6) 3 * 4 = 12 face cards, 3 of which are one of the 13 spades: 9 + 13 = 22: 22/52 = 11/26

- paramvenuLv 77 years ago
Probability of an event = Number of favourable outcomes/Total number of outcomes

1) P(drawing a red king) = 2/52

because out of 4 king cards 2 are red and 2 are black

2) P(drawing a jack or a queen or an ace) = P(drawing a jack + P(drawing a queen) + P(drawing an ace)

= 4/52 + 4/52 + 4/52

= 12/52

3) What is a fade ???? does it mean a face card???

4) P(drawing a heart or a diamond) = P(drawing a heart) + P(drawing a diamond)

= 13/52 + 13/52

= 26/52

TRY to answer the remaining questions...

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- ?Lv 57 years ago
P=desired outcomes/total outcomes

For these questions all of the total outcomes will be 52

There are 2 red kings (2/52 or 1/26)

There are 4 of each type (12/52 or 3/13)

Not sure what a fade is but the probability of something NOT happening is 1- the probability of it happening

there are 13 of each (26/52 or 1/2)

there are 6 black face cards and 2 red aces (8/52 or 2/13)

there are 13 spades and 9 other face cards (NOTE: do not double count the spade face cards) (22/52 or 11/26)

- 7 years ago
1)2/52 There are two red kings

2)3/13 :There are 4 jacks, 4 queens, and 4 aces

3)spade??? 13 spades+ 4 kings- the king in spade=16 P= 1-16/52 36/52

4)1/2 there are 13 hearts and 13 diamonds

5)6/52+2/52=8/52 3 black face card and 2 red ace cards

6)13/52+12/52-3/52=22/52 spades+face- face cards in spades=22

Hopes Face cards are (King, Jack and Queen)

- Karuppasamy KLv 57 years ago
1) 2/52 = 1/26

2) 12/52 = 3/13

3) 36/52 = 9/13

4) 26/52 = 1/2

5) 10/52 = 5/26

6) 25/52

- gollehurLv 43 years ago
The are 4 aces in a regular deck of fifty two enjoying playing cards. So on a single draw (if the deck is full) you could have a 4 in 52 chance of pulling an ace, which reduces to 1 in thirteen. Abstract: 1 in 13 (or 4 in fifty two) which is a 7.6923% chance.

- 3 years ago
can any one help me with the same question but ( a card is drawn from a standard deck of 52 playing cards find the probability that the card is an ace or heart)