How to solve this question......ASAP?

Determine all the possible values of x where 0 deg is more than or equal to x and x is more or equal to 360 deg such that

i'm not sure the solution, please correct it,

sin x sec x - 3 sin x = 0

the solution:

sin x 1/cos x - 3 sin x = 0

sin x - 3 sin x = cos x

then i don't know how to continue....

1 Answer

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  • TC
    Lv 7
    8 years ago
    Favorite Answer

    sinx(secx - 3) = 0

    sinx = 0 or secx = 3

    x = sin - 1 0 or x = sec - 1 3

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