How to solve this question......ASAP?
Determine all the possible values of x where 0 deg is more than or equal to x and x is more or equal to 360 deg such that
i'm not sure the solution, please correct it,
sin x sec x - 3 sin x = 0
sin x 1/cos x - 3 sin x = 0
sin x - 3 sin x = cos x
then i don't know how to continue....
- TCLv 78 years agoFavorite Answer
sinx(secx - 3) = 0
sinx = 0 or secx = 3
x = sin - 1 0 or x = sec - 1 3