Physics moment of inertia?

A 1.7 kg cylinder can rotate about an axle. R=11 cm; L=46.2 cm.

(a) Calculate its moment of inertia about its center.

_____kg·m2

(b) When there's no torque applied, it slows down from 1800 rpm to rest in 51.0 s. Now we want to make it come to rest from 1800 rpm in 7.00 s by applying a constant torque on it. What is the minimum torque applied?

_____m·N

1 Answer

Relevance
  • odu83
    Lv 7
    8 years ago
    Favorite Answer

    θ α ωα

    a) the moment for a solid cylinder is I=.5*m*r^2

    b) first we can calculate the frictional torque

    0=1800*2*pi/60+α*51

    solve for α

    the friction torque is calculate using

    Tf=I*α use I from above along with the α calculated to compute Tf

    Now

    T+Tf=I*α'

    the α' is found by

    0=1800*2*pi/60+α'*7

    combine all together and solve for T

Still have questions? Get your answers by asking now.