## Trending News

Promoted

# Physics moment of inertia?

A 1.7 kg cylinder can rotate about an axle. R=11 cm; L=46.2 cm.

(a) Calculate its moment of inertia about its center.

_____kg·m2

(b) When there's no torque applied, it slows down from 1800 rpm to rest in 51.0 s. Now we want to make it come to rest from 1800 rpm in 7.00 s by applying a constant torque on it. What is the minimum torque applied?

_____m·N

### 1 Answer

Relevance

- odu83Lv 78 years agoFavorite Answer
θ α ωα

a) the moment for a solid cylinder is I=.5*m*r^2

b) first we can calculate the frictional torque

0=1800*2*pi/60+α*51

solve for α

the friction torque is calculate using

Tf=I*α use I from above along with the α calculated to compute Tf

Now

T+Tf=I*α'

the α' is found by

0=1800*2*pi/60+α'*7

combine all together and solve for T

Still have questions? Get your answers by asking now.