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# Find the value of the expression?

6^(2log base6^3 + log base 6^2)

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- morganLv 78 years agoFavorite Answer
Your syntax is difficult to decipher. By the following,

log base 6^2

do you mean?

log_base_6(2)

On that assumption, I'll rewrite the problem:

6^(2*log6(3) + log6(2))

Apply the identity: A*log(B) = log(B^A)

6^(log6(3^2) + log6(2))

Apply the identity: log(A) + log(B) = log(A*B)

6^(log6(3^2 * 2))

6^(log6(18))

Apply the identity: A^logA(X) = X

18

Answer: 18

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