Find the value of the expression?

6^(2log base6^3 + log base 6^2)

1 Answer

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  • morgan
    Lv 7
    8 years ago
    Favorite Answer

    Your syntax is difficult to decipher. By the following,

    log base 6^2

    do you mean?

    log_base_6(2)

    On that assumption, I'll rewrite the problem:

    6^(2*log6(3) + log6(2))

    Apply the identity: A*log(B) = log(B^A)

    6^(log6(3^2) + log6(2))

    Apply the identity: log(A) + log(B) = log(A*B)

    6^(log6(3^2 * 2))

    6^(log6(18))

    Apply the identity: A^logA(X) = X

    18

    Answer: 18

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