Balanced Net Ionic Equation?

Give the balanced net ionic equation for:

the SEPERATION of silver from mercury

(Two equations, one for silver, one for mercury)

2 Answers

  • 8 years ago
    Favorite Answer

    I believe you are referring to the separation of AgCl(s) from Hg2Cl2(s) as in group 1 of the qualitative analysis scheme, or perhaps to a solution containing Ag+ ions and Hg2^2+ ions. If the latter, add some HCl to precipitate both as the insoluble chlorides.

    To the mix of solid AgCl and Hg2Cl2, add ammonia solution, NH3(aq), It will react differently with each solid chloride salt. With AgCl, the addition of NH3 solution will dissolve the solid, producing [Ag(NH3)2]^+, the diamminesilver ion, and the chloride ion. Hg2Cl2, on the other hand, will react with ammonia in a disproportionation reaction, producing metallic Hg, and solid HgNH2Cl2. mercury amidochloride. The latter is white, and the former is black. Therefore, the solid appears gray. The gray precipitate is the confirming test for mercury.

    The solid HgNH2Cl can be separated from the [Ag(NH3)2]+ ions by filtration. The silver ammonia comples, which passes through the filter paper, can be destroyed by adding HNO3, producing solid AgCl once again. This is the confirming test for silver in the analysis scheme.

  • 8 years ago

    ....ok, I honestly don't see the question here....silver separated from mercury...? silver separated from a mercury what? no one is going to be able to answer this question...

Still have questions? Get your answers by asking now.