Anonymous
Anonymous asked in Education & ReferenceHomework Help · 7 years ago

Please someone help me with a math problem? solving for how many seats total in a theater?

Help :( I tried to draw it out lol but its confusing me still

A theater has 11 seats in the first row. each row has 3 more seats than the row in front of it.

if the theatre has 35 rows, how many seats in total are in the theatre?

thank you for your help.

Update:

really?? that was easy. (to the first answer)

Update 2:

I figured the first answer couldn't be right lol.

Something wasn't making sense.

thanks.

4 Answers

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  • 7 years ago
    Best Answer

    The first answer is very wrong because by taking 11 + 3*35

    that would mean there's just one row with 11 seats while the other 35 rows have only 3 seats each.

    Answer to porblem:

    The number of seat per row is 11 + 3*(n-1) with n is the number of row.

    For example:

    First row: n=1 => seats = 11+3*(1-1) = 11

    So on, the number of seats for the:

    Second row = 11 + 3*1

    Third row = 11 + 3*2

    ....

    ...

    35th row = 11 + 3*34

    The total seats in the theatre is determined as the sum of seats in all rows which is:

    First row + second row + ....+ 35th row

    = 11*35 + 3*(1+ 2 + 3 +....+34)

    = 385 + 3*[ (1+34) + (2 + 33) +....+ (16+17)]

    = 385 + 3*[ (35) + (35) + ....+ (35)]

    that makes "35" repeating 16 times

    = 385 + 3*16*35

    = 385 + 1680

    = 2065

    Conclusion: if the theater has 35 rows, there'll be 2065 seats.

  • 7 years ago

    That other guy is wrong by the way, you don't do 11 + 3 x 35, or that just means there are 14 seats in every row. The answer is 487, because you do (11 + 3)35 - 3, -3 being 34 and not counting the first one, because it does not have an extra 3 seats.

  • 7 years ago

    490 seats

    you do 11 + 3 X 35 = 490

    Source(s): i am smart
  • mingo
    Lv 4
    3 years ago

    You want two equations. Let A = Adults and C = youngsters So complete adults + whole children = 500, thus A + C = 500 The 2nd equation involves price $43 per adult and $28 for kids and the total money is 16805. So 2nd equation is 43A + 28C = 16805 A + C = 500 43A + 28C = 16805 Rearrange the 1st equation to remedy for A. A = 500 - C and substitute into the 2d equation. 43(500 - C) + 28C = 16805 Simplify to get 21500 - 43C + 28C = 16805 simplify additional -15C = -4695 and C = 313 so you had 313 children Adults would be 500 - 313 or 187

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