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# improper integral help?

How do I evaluate the integral dx/(x^(2/3)) from -3 to 3?

What I did was, so for the integrand f(x)=1/(x^(2/3)) it's only continuous from (0, infinity), it's discontinuous at x=0, so I set up the integral as the limit as b approaches 0 from the right of the same integrand, so my answer was 3*(3)^(1/3) but that's wrong. Please help me?

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- ?Lv 48 years agoFavorite Answer
Hello echo62,

I have posted a full solution to your question at one of the math help forums I collaborate with, so that I may give you an easy to read explanation using LaTeX:

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