Anonymous
Anonymous asked in Science & MathematicsMathematics · 7 years ago

Find two numbers whose difference is 96 and whose product is a minimum?

How do I solve a problem like this?

2 Answers

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  • 7 years ago
    Favorite Answer

    The product is x * (x - 96) = x^2 - 96x

    Taking the derivative, we get 2x - 96. Any local minimum or maximum will be found where the derivative equals zero, so 2x - 96 = 0 and x = 48.

    The numbers are -48 and 48, and their product is -2304.

  • ?
    Lv 7
    7 years ago

    I don't know any other way to solve it but to think about it a bit... and - assuming integers - I come up with -95 and 1. At first I was thinking 0 and 96, but then I saw it. It's -95 and 1.

    Source(s): I know math, but had to solve this one by intuition
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