Find two numbers whose difference is 96 and whose product is a minimum?
How do I solve a problem like this?
- Jenna KLv 67 years agoFavorite Answer
The product is x * (x - 96) = x^2 - 96x
Taking the derivative, we get 2x - 96. Any local minimum or maximum will be found where the derivative equals zero, so 2x - 96 = 0 and x = 48.
The numbers are -48 and 48, and their product is -2304.
- ?Lv 77 years ago
I don't know any other way to solve it but to think about it a bit... and - assuming integers - I come up with -95 and 1. At first I was thinking 0 and 96, but then I saw it. It's -95 and 1.Source(s): I know math, but had to solve this one by intuition