Identifying vertex, axis of symmetry, and x- intercepts.?

Identify the vertex, axis of symmetry, and x-intercepts.

f(x) =

1/5(x^2 + 2x − 5)

vertex

(x, y) = ( , )

axis of symmetry

x-intercepts

(x, y) = ( , ) (smaller x-value)

(x, y) = ( , ) (larger x-value)

Check your results algebraically by writing the quadratic function in standard form. (Use y for f(x).)

1 Answer

Relevance
  • 7 years ago
    Best Answer

    1/5*X^2+2/5*X-1

    Standard form: a(X-h)²+k = ( 1/5X² +2/5X +1/5) -1/5 -1 = 1/5(X +1)² -6/5

    X = -1 ±√( 6) = -3.4495, or 1.4495

    Axis of symmetry: X= -1; Vertex (minimum)=(h,k)=( -1, -6/5); y-intercept is (0,-1)

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