enable L = length; w=width Perimeter = 2L + 2w = 40 4 Or L + W = 22 (dividing perimeter by potential of two) enable W = 22 - L Substituting for W and L contained in the area function (L)(22 - L) = 40 22 L - L^2 = 40 Rewrite into commonplace quadratic style L^2 - 22L + 40 = 0 Factoring by potential of using FOIL approach (L - 20)(L - 2) = 0 So, L = 20 or 2 If L = 20, W = 22 - L = 2 So, W = 2, L = 20 If we tried L = 2 W = 22 - L W = 2 So W = 20; L = 2 by potential of convention, the longer section is denoted by potential of L so L = 20, W = 2 both way, the size of rectangle are 2 yards x 20 yards