Wizdom asked in Science & MathematicsChemistry · 8 years ago

Given 1M Tris (pH 8) and 0.5 M EDTA stock solutions, need to prepare 50 mL of TE (pH 8). What volumes?

Given 1M Tris (pH 8) and 0.5 M EDTA stock solutions, prepare 50 mL of TE (pH 8). What volumes of the Tris stock, EDTA stock and deionized water do you need?

Volume TRIS ______________ Volume EDTA ____________

Volume H2O___________

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• 8 years ago

According to a previous question that I answered:

'... The "recipe" for TE is 10 mM Tris-Cl and 1mM EDTA ...'

The asker should have included that info in the question.

The current problem is virtually identical to the previous one, except that the target volume here is 50 mL, where it was 200 mL in the previous.

M1V1 = M2V2

For Tris-Cl:

M2 =10 mM Tris-Cl

V2 = 50 mL

M1 = 1 M Tris-Cl,

V1 = unknown

M1V1 = M2V2

V1 = M2V2/M1

V1 = (10 mM)*(50 mL)/(1 M)

V1 = 500 mmL = 0.5 mL

For EDTA:

M2 = 1 mM EDTA

V2 = 50 mL

M1 = 0.5 M EDTA

V1 = unknown

M1V1 = M2V2

V1 = M2V2/M1

V1 = (1 mM)*(50 mL)/0.5 M)

V1 = 100 mmL = 0.1 mL

So pipet 0.5 mL of the 1 M Tris-Cl and 0.1 mL of the 1 mM EDTA solutions into a 50-mL volumetric flask and dilute to volume with deionized or distilled water (with adjust for pH if necessary, of course).

• 8 years ago

What's Tris?

What's TE??